[nflug] PHP character question

[Robert Meyer]

Well, a couple of observations...  You never quote any of the characters that you're assigning.  I'm not sure if it's an omission or what.

Second, in the chunk of code with the ||, the first piece of code with give a a '|' for *every* character.  For the second, you will get two for every character that is not M or Z and one for each M or Z.

Maybe a cut and paste of the whole code fragment might help figure out what's going on.

Cheers!

Bob
 
--
"When once you have tasted flight, you will forever walk the earth with your eyes turned skyward, for there you have been, and there you will always long to return."
   --Leonardo da Vinci

----- Original Message ----
From: Rob Dege <livemotion at gmail.com>
To: nflug at nflug.org
Sent: Friday, April 18, 2008 12:22:35 PM
Subject: [nflug] PHP character question

Hello to all,

I am trying to create a simple for loop, but instead of incrementing numbers, I want to increment characters.  I am able to get the code to work, up until the end, when it comes time to output the last char.

for ($i = A; $i < Z; $i++)
  {
    echo "$i <br>";
   }

In this simple example, the output would be to echo the characters A - Y, omitting Z; which is expected.  If I change $i < Z to $i <= Z, one would expect to have Z included in the output.  Unfortunately, this does not happen.  Instead, it continues to loop past Z until it outputs YZ (A - Z, AA - AZ, BA - BZ, ..... YA - YZ).  This would imply that it's matching against ZA instead of just Z.  I know there are alternate ways around this, but now I'm really curious about the looping behavior here.  Any insight is appreciated.


I also have a related question with an if condition, if you want further head scratching.

if ($i != M || $i != Z) { echo " | "; }

With this statement, whenever $i has the value of either M or Z it should execute the condition, but it doesn't.  However, if I separate the if condition into two separate conditions statements, it works as intended.

if ($i != M) { echo " | "; }

if ($i != Z) { echo " | "; }

I'm not sure why the || would cause a problem, but for some reason it does.

-- 
-Rob

Ben Franklin Quote: "They that can give up essential liberty to obtain a little temporary safety deserve neither liberty nor safety."





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